Chapter 12ICSE Class 10 Maths100% Free

Reflection — Important Questions

13 hand-picked ICSE Class 10 Maths important questions for Reflection, each with a full model answer — the formats and topics most likely to appear in your board exam.

13
Questions
6
Question types
32
Total marks
₹0
With answers
Quick answer

High-yield ICSE Reflection questions ask for images under reflection in the xx-axis (x,y)(x,y)(x,y)\to(x,-y), the yy-axis (x,y)(x,y)(x,y)\to(-x,y) and the origin (x,y)(x,y)(x,y)\to(-x,-y), identifying invariant points, and plotting points with their images on graph paper. Reflection in the lines x=ax=a and y=by=b also appears.

About Reflection

In the ICSE Class 10 Maths chapter Reflection you find the image of a point when it is reflected in the coordinate axes, in the origin, and in lines parallel to the axes. You also identify invariant points and plot points and their images on graph paper to name the figure formed.

Reflection in the $x$-axisReflection in the $y$-axisReflection in the originInvariant pointsPlotting images on graph paper

Key concepts & formulas

Reflection in the axes

Mx:(x,y)(x,y)M_x:(x,y)\to(x,-y) (reflection in the xx-axis); My:(x,y)(x,y)M_y:(x,y)\to(-x,y) (reflection in the yy-axis).

Reflection in the origin

(x,y)(x,y)(x,y)\to(-x,-y). Reflecting in the xx-axis and then the yy-axis (in either order) gives the same result as reflection in the origin.

Invariant points

A point is invariant if its image is itself. Under MxM_x every point on the xx-axis is invariant; under MyM_y every point on the yy-axis is invariant.

Reflection in $x=a$ and $y=b$

(x,y)(2ax,y)(x,y)\to(2a-x,\,y) for the line x=ax=a; (x,y)(x,2by)(x,y)\to(x,\,2b-y) for the line y=by=b.

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Important questions with answers

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Question typeCountMarks
MCQ41
Assertion–Reason11
Very Short22
Short Answer33
Long Answer25
Case-based14

Multiple-choice questions (1 mark)

Q1MCQEasy1 mark

The image of the point (3,5)(3,-5) under reflection in the xx-axis is:

  1. (a)

    (3,5)(3,5)

  2. (b)

    (3,5)(-3,-5)

  3. (c)

    (3,5)(-3,5)

  4. (d)

    (5,3)(-5,3)

Show model answer

Answer: (a) (3,5)(3,5).

Reflection in the xx-axis sends (x,y)(x,y)(x,y)\to(x,-y), so (3,5)(3,5)(3,-5)\to(3,5).

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Q2MCQEasy1 mark

The image of the point (4,7)(4,7) under reflection in the yy-axis is:

  1. (a)

    (4,7)(-4,7)

  2. (b)

    (4,7)(4,-7)

  3. (c)

    (4,7)(-4,-7)

  4. (d)

    (7,4)(7,4)

Show model answer

Answer: (a) (4,7)(-4,7).

Reflection in the yy-axis sends (x,y)(x,y)(x,y)\to(-x,y), so (4,7)(4,7)(4,7)\to(-4,7).

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Q3MCQModerate1 mark

The point (2,6)(-2,6) is reflected in the origin. Its image is:

  1. (a)

    (2,6)(2,-6)

  2. (b)

    (2,6)(-2,-6)

  3. (c)

    (2,6)(2,6)

  4. (d)

    (6,2)(6,-2)

Show model answer

Answer: (a) (2,6)(2,-6).

Reflection in the origin sends (x,y)(x,y)(x,y)\to(-x,-y), so (2,6)(2,6)(-2,6)\to(2,-6).

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Q4MCQHOTS1 mark

The image of the point (3,4)(-3,4) under reflection in the line x=1x=1 is:

  1. (a)

    (5,4)(5,4)

  2. (b)

    (5,4)(-5,4)

  3. (c)

    (5,4)(5,-4)

  4. (d)

    (1,4)(-1,4)

Show model answer

Answer: (a) (5,4)(5,4).

Reflection in x=ax=a sends (x,y)(2ax,y)(x,y)\to(2a-x,y). With a=1a=1: (2(1)(3),4)=(5,4)(2(1)-(-3),\,4)=(5,4).

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Assertion–Reason questions (1 mark)

Q5Assertion–ReasonModerate1 mark

Assertion (A): The point (0,5)(0,5) is invariant under reflection in the yy-axis.

Reason (R): Every point on the yy-axis maps to itself under reflection in the yy-axis.

  1. (a)

    Both A and R are true and R is the correct explanation of A

  2. (b)

    Both A and R are true but R is not the correct explanation of A

  3. (c)

    A is true but R is false

  4. (d)

    A is false but R is true

Show model answer

Answer: (a) My(0,5)=(0,5)=(0,5)M_y(0,5)=(-0,5)=(0,5), so the point is invariant, and since it lies on the yy-axis, R correctly explains A.

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Very short answer questions (2 marks)

Q6Very ShortEasy2 marks

Find the image of the point (6,2)(6,-2) under reflection in (i) the xx-axis, (ii) the origin.

Show model answer

(i) Mx:(6,2)(6,2).M_x:(6,-2)\to(6,2).

(ii) Origin: (6,2)(6,2).(6,-2)\to(-6,2).

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Q7Very ShortModerate2 marks

The image of a point PP under reflection in the xx-axis is (4,5)(-4,5). Find (i) the coordinates of PP, and (ii) the image of PP under reflection in the yy-axis.

Show model answer

(i) Since Mx:(x,y)(x,y)M_x:(x,y)\to(x,-y), if the image is (4,5)(-4,5) then P=(4,5).P=(-4,-5).

(ii) My(4,5)=(4,5).M_y(-4,-5)=(4,-5).

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Short answer questions (3 marks)

Q8Short AnswerModerate3 marks

The point A(4,2)A(-4,2) is given. Find (i) BB, the image of AA under reflection in the origin, (ii) CC, the image of AA under reflection in the xx-axis, and (iii) state whether BB and CC have the same xx-coordinate.

Show model answer

(i) Origin: B=(4,2).B=(4,-2).

(ii) MxM_x: C=(4,2).C=(-4,-2).

(iii) BB has xx-coordinate 44 and CC has xx-coordinate 4-4; they are different (they are negatives of each other).

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Q9Short AnswerEasy3 marks

Plot the point A(1,2)A(1,2) on graph paper. Mark AA', its image under reflection in the xx-axis, and AA'', its image under reflection in the yy-axis. Write the coordinates of AA' and AA''.

Show model answer

A=Mx(1,2)=(1,2)A'=M_x(1,2)=(1,-2) and A=My(1,2)=(1,2).A''=M_y(1,2)=(-1,2).

ICSE Class 10 Maths — Reflection: Plot the point A(1,2) on graph paper. Mark A', its image under reflection in the x-axis, and A'', its image under reflection in the y-axis. Write
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Q10Short AnswerHOTS3 marks

For the point (3,5)(3,5), show that reflecting in the xx-axis and then in the yy-axis gives the same image as a single reflection in the origin.

Show model answer

Reflect in the xx-axis: Mx(3,5)=(3,5).M_x(3,5)=(3,-5).

Now reflect this in the yy-axis: My(3,5)=(3,5).M_y(3,-5)=(-3,-5).

Reflection of (3,5)(3,5) in the origin: (x,y)(x,y)(x,y)\to(-x,-y) gives (3,5).(-3,-5).

Both routes give (3,5)(-3,-5), so reflection in the xx-axis followed by the yy-axis equals reflection in the origin.

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Long answer questions (5 marks)

Q11Long AnswerModerate5 marks

The point A(4,3)A(4,3) is given. Let BB be its image under reflection in the yy-axis, CC its image under reflection in the origin, and DD its image under reflection in the xx-axis. (i) Write the coordinates of BB, CC and DD. (ii) Name the figure ABCDABCD. (iii) Find its area.

Show model answer

(i) B=My(4,3)=(4,3)B=M_y(4,3)=(-4,3); C=(4,3)C=(-4,-3) (origin); D=Mx(4,3)=(4,3).D=M_x(4,3)=(4,-3).

(ii) The four points A(4,3),B(4,3),C(4,3),D(4,3)A(4,3),\,B(-4,3),\,C(-4,-3),\,D(4,-3) form a rectangle (its sides are parallel to the axes).

(iii) Length AB=8AB=8 units and breadth AD=6AD=6 units, so area =8×6=48=8\times6=48 square units.

ICSE Class 10 Maths — Reflection: The point A(4,3) is given. Let B be its image under reflection in the y-axis, C its image under reflection in the origin, and D its image under re
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Q12Long AnswerHOTS5 marks

The triangle with vertices P(1,2)P(1,2), Q(4,2)Q(4,2) and R(4,5)R(4,5) is reflected in the xx-axis to give triangle PQRP'Q'R'. (i) Write the coordinates of PP', QQ', RR'. (ii) Find the area of triangle PQRPQR. (iii) State the relation between the areas of the two triangles.

Show model answer

(i) MxM_x sends (x,y)(x,y)(x,y)\to(x,-y): P=(1,2), Q=(4,2), R=(4,5).P'=(1,-2),\ Q'=(4,-2),\ R'=(4,-5).

(ii) PQR\triangle PQR is right-angled at QQ with base PQ=3PQ=3 and height QR=3QR=3, so area =12×3×3=4.5=\tfrac12\times3\times3=4.5 square units.

(iii) Reflection preserves size and shape, so PQR\triangle P'Q'R' is congruent to PQR\triangle PQR and also has area 4.54.5 square units.

ICSE Class 10 Maths — Reflection: The triangle with vertices P(1,2), Q(4,2) and R(4,5) is reflected in the x-axis to give triangle P'Q'R'. (i) Write the coordinates of P', Q', R'.
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Case-based questions (4 marks)

Q13Case-basedModerate4 marks

A graphic designer places a key point of a logo at K(3,5)K(3,5) on a coordinate grid and creates images of it by reflection.

(i) Find the image of KK under reflection in the xx-axis.

(ii) Find the image of KK under reflection in the yy-axis.

(iii) Find the image of KK under reflection in the origin.

(iv) Which single reflection above gives the same point as reflecting KK first in the xx-axis and then in the yy-axis?

Show model answer

(i) Mx(3,5)=(3,5).M_x(3,5)=(3,-5).

(ii) My(3,5)=(3,5).M_y(3,5)=(-3,5).

(iii) Origin: (3,5)(3,5).(3,5)\to(-3,-5).

(iv) Reflecting first in the xx-axis then the yy-axis: (3,5)(3,5)(3,5)(3,5)\to(3,-5)\to(-3,-5), which is the reflection in the origin from part (iii).

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