Linear Inequations (In One Variable) — ICSE Class 10 Maths Important Questions
13 ICSE Class 10 Maths practice questions on Linear Inequations (In One Variable), each with a full model answer, covering 5 topics from the chapter in the question formats used in the exam.
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- Key concepts
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Linear Inequations (In One Variable) — ICSE Class 10 Maths Important Questions
Inequalities on the Number Line
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Start your Freemium planReliable-scoring ICSE Linear Inequations questions ask you to solve an inequation in one variable over a stated replacement set (natural numbers, integers or real numbers), write the solution set, and represent it on a number line. Remember to reverse the inequality sign when multiplying or dividing by a negative number. Combined (double) inequations with fractions are asked almost every year.
About Linear Inequations (In One Variable)
Within the ICSE Class 10 Maths chapter Linear Inequations you solve inequalities in one variable, taking care to reverse the sign when multiplying or dividing by a negative number. The solution depends on the replacement set — natural numbers, whole numbers, integers or real numbers — and you write the solution set and show it on a number line.
Key concepts & formulas
You may add or subtract any quantity, and multiply or divide by any positive number, without changing the sign. Multiplying or dividing both sides by a negative number reverses the inequality: from -x>3 you get x<-3.
The replacement set is the set from which x may be chosen (e.g. N,W,Z,R). The solution set is the subset that satisfies the inequation — it may be finite (for integers) or an interval (for real numbers).
On the number line a filled (solid) dot means the end value is included (≤,≥) and an open dot means it is excluded (<,>). For real solutions the whole segment is shaded; for integers only the marked points are shown.
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Important questions with answers
Try each on paper first, then reveal the model answer to check your method.
Multiple-choice questions (1 mark)
If x is a natural number and x<4, the solution set is:
- (a)
\1,2,3\
- (b)
\0,1,2,3\
- (c)
\1,2,3,4\
- (d)
\0,1,2,3,4\
Show model answer
Answer: (a) \1,2,3\.
Natural numbers start at 1, and x<4 excludes 4, so x\1,2,3\.
The solution of 2x>6, where xR, is:
- (a)
x>3
- (b)
x<3
- (c)
x≥3
- (d)
x>6
Show model answer
Answer: (a) x>3.
Dividing both sides by the positive number 2 keeps the sign: x>3.
The solution of -3x≥9, where xR, is:
- (a)
x≤-3
- (b)
x≥-3
- (c)
x≤3
- (d)
x≥3
Show model answer
Answer: (a) x≤-3.
Dividing by -3 reverses the sign: x≤9/-3=-3.
The solution set of 3≤2x-1<7, where xZ, is:
- (a)
\2,3\
- (b)
\2,3,4\
- (c)
\3\
- (d)
\2\
Show model answer
Answer: (a) \2,3\.
3≤2x-14≤2x x≥2; and 2x-1<72x<8 x<4. So 2≤ x<4, giving integers \2,3\.
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Practise free with the AI tutor →Assertion–Reason questions (1 mark)
Assertion (A): Multiplying both sides of -x>3 by -1 gives x>-3.
Reason (R): When both sides of an inequation are multiplied by a negative number, the inequality sign reverses.
- (a)
Both A and R are true and R is the correct explanation of A
- (b)
Both A and R are true but R is not the correct explanation of A
- (c)
A is true but R is false
- (d)
A is false but R is true
Show model answer
Answer: (d) R is true, but A is false: multiplying -x>3 by -1 reverses the sign to give x<-3, not x>-3.
Very short answer questions (2 marks)
Solve the inequation 5x-3<3x+7, where xR.
Show model answer
5x-3<3x+7
5x-3x<7+3
2x<10 x<5.
Solution set =\x:x<5, xR\.
Given the replacement set \-2,-1,0,1,2,3\, find the solution set of 2x-1<3.
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2x-1<32x<4 x<2.
From the replacement set, the values less than 2 are -2,-1,0,1.
Solution set =\-2,-1,0,1\.
Short answer questions (3 marks)
Solve -2≤ x+3<5, where xR, and represent the solution on a number line.
Show model answer
Subtract 3 throughout: -2-3≤ x<5-3, i.e. -5≤ x<2.
Solution set =\x:-5≤ x<2, xR\ — a solid dot at -5 (included) and an open dot at 2 (excluded).
Solve x/2+5/3+6, where xR.
Show model answer
Multiply every term by 6 (the LCM):
6×x/2+6×5≤6×x/3+6×6
3x+30≤2x+36
3x-2x≤36-30 x≤6.
Solution set =\x:x≤6, xR\.
If x is an integer and -5<2x-1≤5, find the solution set and state its greatest value.
Show model answer
-5<2x-1-4<2x x>-2.
2x-1≤52x≤6 x≤3.
So -2<x≤3. For integers, the solution set =\-1,0,1,2,3\, and its greatest value is 3.
Long answer questions (5 marks)
Solve the pair of inequations 3x-2>2(x-1) and 2x+5≤15 simultaneously, where xR, and represent the solution on a number line.
Show model answer
First inequation: 3x-2>2x-23x-2x>-2+2 x>0.
Second inequation: 2x+5≤152x≤10 x≤5.
Common solution: 0<x≤5.
Solution set =\x:0<x≤5, xR\ — open dot at 0, solid dot at 5.
Solve the following inequation, write the solution set and represent it on a number line: -3(x-7)≥15-7x>x+1/3, where xR.
Show model answer
Split into two inequations.
Left part: -3(x-7)≥15-7x-3x+21≥15-7x-3x+7x≥15-214x≥-6 x≥-3/2.
Right part: 15-7x>x+1/3. Multiply by 3: 45-21x>x+145-1>x+21x44>22x x<2.
Combining: -3/2≤ x<2.
Solution set =\x:-1.5≤ x<2, xR\ — solid dot at -1.5, open dot at 2.
Case-based questions (4 marks)
The replacement set for the variable x is the set of integers Z. Consider the inequation -4≤3x+2<11.
(i) Solve the inequation for x.
(ii) Write the solution set.
(iii) State the number of elements in the solution set.
(iv) Represent the solution on a number line.
Show model answer
(i) -4≤3x+2-6≤3x x≥-2; and 3x+2<113x<9 x<3. So -2≤ x<3.
(ii) For integers, solution set =\-2,-1,0,1,2\.
(iii) It has 5 elements.
(iv) Mark the five integer points -2 to 2 with solid dots.
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Frequently asked questions
Do these Linear Inequations (In One Variable) questions follow the latest ICSE syllabus?
Yes — they are aligned to the CISCE 2026–27 syllabus for ICSE Class 10 Maths, so nothing here is outside the current course.
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