Exploring Mixtures and their Separation — CBSE Class 9 Science Important Questions
13 hand-picked CBSE Class 9 Science important questions for Exploring Mixtures and their Separation, each with a full model answer — the formats and topics most likely to appear in your board exam.
- 13
- Questions
- 6
- Question types
- 32
- Total marks
- ₹0
- With answers
The highest-yield questions ask you to classify mixtures as homogeneous or heterogeneous, distinguish true solutions, colloids and suspensions using the Tyndall effect and particle size, and choose the right separation technique (filtration, evaporation, crystallisation, distillation, fractional distillation, chromatography, separating funnel). Mass-by-mass concentration numericals appear often.
About Exploring Mixtures and their Separation
This chapter is about mixtures — substances made of two or more components not chemically combined — and the physical methods used to separate them. It covers homogeneous versus heterogeneous mixtures, the differences between true solutions, colloids and suspensions, concentration of solutions, and separation techniques such as filtration, evaporation, distillation, chromatography and using a separating funnel.
Key concepts & formulas
A homogeneous mixture has a uniform composition throughout (e.g. salt in water); a heterogeneous mixture does not (e.g. sand in water). Colloids and suspensions are heterogeneous.
By particle size: true solution (<1 nm, no Tyndall effect, stable), colloid (1–100 nm, shows Tyndall effect, does not settle), suspension (>100 nm, settles on standing, particles visible).
Mass by mass percentage =mass of solute/mass of solution×100, where mass of solution = mass of solute + mass of solvent.
Match the method to the property difference: filtration (insoluble solid + liquid), evaporation/crystallisation (dissolved solid), distillation (miscible liquids), separating funnel (immiscible liquids), chromatography (dissolved coloured components).
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Important questions with answers
Try each on paper first, then reveal the model answer to check your method.
| Question type | Count | Marks |
|---|---|---|
| MCQ | 4 | 1 |
| Assertion–Reason | 1 | 1 |
| Very Short | 2 | 2 |
| Short Answer | 3 | 3 |
| Long Answer | 2 | 5 |
| Case-based | 1 | 4 |
Multiple-choice questions (1 mark)
Which of the following is a homogeneous mixture?
- (a)
Sand and water
- (b)
Salt dissolved in water
- (c)
Oil and water
- (d)
Chalk powder in water
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Answer: (b) Salt dissolved in water.
Salt dissolves completely to give a uniform composition throughout, so it is homogeneous. The other three are heterogeneous because their components stay in separate, visible phases.
The scattering of a beam of light by the tiny particles of a colloid, making the path of light visible, is called the:
- (a)
Brownian motion
- (b)
Tyndall effect
- (c)
Sedimentation
- (d)
Diffusion
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Answer: (b) Tyndall effect.
Colloidal particles (1–100 nm) are large enough to scatter light, so the beam's path becomes visible. True solutions do not show this effect.
A mixture of two miscible liquids whose boiling points differ by less than 25 K is best separated by:
- (a)
Simple distillation
- (b)
Fractional distillation
- (c)
Filtration
- (d)
Using a separating funnel
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Answer: (b) Fractional distillation.
When boiling points are close (difference <25 K), a fractionating column is needed to allow repeated evaporation and condensation. Simple distillation works only when the difference is large.
To obtain pure common salt from sea water, which sequence of processes is used?
- (a)
Filtration followed by chromatography
- (b)
Evaporation followed by crystallisation
- (c)
Sublimation followed by distillation
- (d)
Centrifugation followed by filtration
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Answer: (b) Evaporation followed by crystallisation.
Sea water is evaporated to obtain crude salt, which is then dissolved and crystallised to remove soluble impurities. Crystallisation gives a purer solid than simple evaporation because impurities remain in the mother liquor.
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Practise free with the AI tutor →Assertion–Reason questions (1 mark)
Assertion (A): A colloid is a heterogeneous mixture.
Reason (R): The particles of a colloid are large enough to settle down on their own on standing.
- (a)
Both A and R are true and R is the correct explanation of A
- (b)
Both A and R are true but R is not the correct explanation of A
- (c)
A is true but R is false
- (d)
A is false but R is true
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Answer: (c) A is true but R is false. A colloid is indeed heterogeneous, but its particles do not settle on standing; they remain dispersed and can be separated only by centrifugation. Only suspension particles settle down.
Very short answer questions (2 marks)
Define a solution. Name its two components and give one everyday example.
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A solution is a homogeneous mixture of two or more substances. Its components are the solute (present in smaller amount, gets dissolved) and the solvent (present in larger amount, does the dissolving).
Example: sugar dissolved in water — sugar is the solute and water is the solvent.
A mixture contains common salt and ammonium chloride. Which technique separates them, and why does it work?
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The two are separated by sublimation.
On heating, ammonium chloride changes directly from solid to vapour (it sublimes) and re-solidifies on a cool surface, while common salt does not sublime and is left behind. The difference in the ability to sublime allows the separation.
Short answer questions (3 marks)
A solution contains 40 g of common salt dissolved in 320 g of water. Calculate the concentration of the solution in terms of mass by mass percentage.
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Mass of solute (salt) =40 g and mass of solvent (water) =320 g.
Mass of solution =40+320=360 g.
Mass by mass \%=mass of solute/mass of solution×100=40/360×100
=11.1\% (approximately).
So the solution is about 11.1\% salt by mass.
Explain, with a labelled diagram, how a mixture of kerosene and water can be separated.
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Kerosene and water are immiscible liquids (they do not mix and form two separate layers), so they are separated using a separating funnel.
The mixture is poured into the funnel and allowed to stand. The denser water settles at the bottom and lighter kerosene floats on top. On opening the stopcock, the lower water layer runs out first; the stopcock is closed as soon as the water is drained, leaving kerosene behind.
You are given a mixture of iron filings, ammonium chloride, common salt and sand. Explain the sequence of steps to separate all four components.
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The components differ in magnetism, ability to sublime and solubility, so they are separated in stages:
Step 1 — Magnet: Move a magnet through the mixture; the iron filings are attracted and removed.
Step 2 — Sublimation: Heat the remaining mixture; ammonium chloride sublimes and is collected as a solid on a cool surface.
Step 3 — Dissolving and filtration: Add water to the leftover (salt + sand). Salt dissolves; sand remains insoluble and is separated by filtration (sand is the residue).
Step 4 — Evaporation: Heat the filtrate to evaporate the water, leaving behind common salt.
All four components are thus recovered.
Long answer questions (5 marks)
Explain the process of distillation with a labelled diagram. How does fractional distillation differ from it, and where is each used?
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Distillation is used to separate a mixture of a non-volatile solid dissolved in a liquid, or two miscible liquids with a large difference in boiling points. The mixture is heated in a distillation flask; the liquid with the lower boiling point vaporises, passes through a condenser where it cools back to liquid, and is collected as the distillate. The non-volatile component is left behind.
Fractional distillation is used when two miscible liquids have boiling points differing by less than 25 K (e.g. separating the gases of air, or components of petroleum). It uses an extra fractionating column (packed with glass beads) fitted between the flask and the condenser. The beads provide surface for repeated evaporation and condensation, so the vapour becomes progressively richer in the lower-boiling liquid before it reaches the condenser.
Difference: simple distillation has no fractionating column and works only when boiling points are far apart; fractional distillation uses a column and separates liquids with close boiling points.
Classify mixtures using a tree diagram. Then compare true solutions, colloids and suspensions on the basis of particle size, appearance, the Tyndall effect and settling, and name the different types of colloids with one example each.
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Mixtures can be classified as shown:
Comparison:
- True solution: particle size <1 nm; transparent; no Tyndall effect; does not settle; homogeneous. Example: sugar in water.
- Colloid: particle size 1–100 nm; appears uniform but is heterogeneous; shows Tyndall effect; does not settle (needs centrifugation). Example: milk.
- Suspension: particle size >100 nm; particles visible; shows Tyndall effect; settles on standing and can be filtered; heterogeneous. Example: chalk in water.
Types of colloids (by dispersed phase and medium):
- Foam (gas in liquid): shaving cream.
- Emulsion (liquid in liquid): milk.
- Sol (solid in liquid): ink, paint.
- Aerosol (liquid in gas): fog or clouds.
- Gel (liquid in solid): jelly, cheese.
Case-based questions (4 marks)
Read the passage and answer the questions.
Riya noticed that the black ink used in her sketch pen is actually a mixture of several coloured dyes. Her teacher put a small drop of the ink near the bottom of a strip of filter paper and dipped the lower edge of the strip in water, keeping the ink spot just above the water level. As the water slowly rose up the paper, the ink spot separated into bands of different colours because the dyes travel at different speeds.
(i) Name the separation technique described in the passage.
(ii) On what property of the components does this technique depend?
(iii) Why must the ink spot be kept above the water level and not dipped in the water?
(iv) State one other everyday application of this technique.
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(i) The technique is chromatography (paper chromatography).
(ii) It depends on the difference in the rates at which the components move up the paper — i.e. their differing solubility in the solvent and their differing tendency to be adsorbed on the paper. Components that are more soluble and less strongly held travel faster and farther.
(iii) If the ink spot were dipped in the water, the dyes would simply dissolve into the water in the container and wash away instead of rising up the paper and separating into distinct bands. Keeping the spot above the water level lets the solvent rise through the spot and carry the dyes up.
(iv) It is used to separate coloured pigments from a plant extract (or to detect drugs/additives in blood and to separate the coloured constituents of a natural dye).
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Yes. All 13 CBSE Class 9 Science important questions for Exploring Mixtures and their Separation are free, with full model answers and no login required.Do these Exploring Mixtures and their Separation questions follow the latest CBSE syllabus?
Yes — they are aligned to the NCERT 2026–27 syllabus for CBSE Class 9 Science, so nothing here is outside the current course.How should I practise the Exploring Mixtures and their Separation important questions?
Attempt each question on paper first, then reveal the model answer to check your method — not just the final result. Re-do anything you got wrong the same day.What types of questions are covered for Exploring Mixtures and their Separation?
A full mix — multiple-choice questions, assertion–reason questions, very short answer questions, short answer questions, long answer questions, case-based questions — so every format in the CBSE paper is covered.
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