Chapter 1ICSE Class 9 Chemistry100% Free

The Language of ChemistryICSE Class 9 Chemistry Important Questions

13 hand-picked ICSE Class 9 Chemistry important questions for The Language of Chemistry, each with a full model answer — the formats and topics most likely to appear in your board exam.

13
Questions
6
Question types
32
Total marks
₹0
With answers
Quick answer

High-yield ICSE Language of Chemistry questions cover writing symbols and valencies, deriving chemical formulae by the criss-cross method, and balancing equations by the hit-and-trial method. Expect valency-based formula writing (e.g. Al2(SO4)3Al_2(SO_4)_3Al_2(SO_4)_3), converting word equations to balanced symbolic equations with state symbols, and defining terms like radical, molecular formula and variable valency.

About The Language of Chemistry

In the ICSE Class 9 Chemistry chapter The Language of Chemistry you learn the shorthand chemistry uses to describe matter: symbols of elements, valency, acid and basic radicals, writing chemical formulae by balancing valencies, and framing balanced chemical equations complete with state symbols and conditions. It is the grammar on which all later chemistry is built.

Symbols and atomicity of elementsValency and variable valencyAcidic and basic radicalsWriting chemical formulae (criss-cross method)Balancing chemical equations

Key concepts & formulas

Valency

Valency is the combining capacity of an element, i.e. the number of hydrogen atoms (or their equivalent) that combine with or replace one atom of the element. In a compound the total positive valency equals the total negative valency.

Criss-cross method

Write the symbols of the radicals with their valencies, then cross-multiply the valency of each onto the other as a subscript, e.g. Al3+Al^{3+}Al^3+ and SO42SO_4^{2-}SO_4^2- give Al2(SO4)3Al_2(SO_4)_3Al_2(SO_4)_3.

Balanced equation

A chemical equation is balanced when the number of atoms of each element is equal on both sides, obeying the law of conservation of mass. State symbols (s),(l),(g),(aq)(s),(l),(g),(aq)(s),(l),(g),(aq) and conditions are added over the arrow.

Variable valency

Some elements show more than one valency; the lower is named with the suffix -ous and the higher with -ic, e.g. iron: Fe2+Fe^{2+}Fe^2+ (ferrous) and Fe3+Fe^{3+}Fe^3+ (ferric).

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Important questions with answers

Try each on paper first, then reveal the model answer to check your method.

Question typeCountMarks
MCQ41
Assertion–Reason11
Very Short22
Short Answer33
Long Answer25
Case-based14

Multiple-choice questions (1 mark)

Q1MCQEasy1 mark

The correct chemical formula of aluminium sulphate is:

  1. (a)

    Al2SO4Al_2SO_4Al_2SO_4

  2. (b)

    Al2(SO4)3Al_2(SO_4)_3Al_2(SO_4)_3

  3. (c)

    AlSO4AlSO_4AlSO_4

  4. (d)

    Al3(SO4)2Al_3(SO_4)_2Al_3(SO_4)_2

Show model answer

Answer: (b) Al2(SO4)3Al_2(SO_4)_3Al_2(SO_4)_3.

Aluminium is Al3+Al^{3+}Al^3+ and sulphate is SO42SO_4^{2-}SO_4^2-. Cross-multiplying the valencies gives two aluminium ions and three sulphate ions: Al2(SO4)3Al_2(SO_4)_3Al_2(SO_4)_3.

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Q2MCQEasy1 mark

Which of the following is the symbol of the element sodium?

  1. (a)

    SSS

  2. (b)

    SoSoSo

  3. (c)

    NaNaNa

  4. (d)

    SnSnSn

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Answer: (c) NaNaNa.

The symbol of sodium comes from its Latin name natrium, so it is NaNaNa. SSS is sulphur and SnSnSn (stannum) is tin.

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Q3MCQModerate1 mark

The valency of nitrogen in ammonia, NH3NH_3NH_3, is:

  1. (a)

    111

  2. (b)

    222

  3. (c)

    333

  4. (d)

    555

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Answer: (c) 333.

Each hydrogen has a valency of 111, and three hydrogen atoms combine with one nitrogen atom. Hence nitrogen exercises a valency of 333 in NH3NH_3NH_3.

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Q4MCQHOTS1 mark

In the reaction aFe+bH2OFe3O4+cH2aFe + bH_2O \rightarrow Fe_3O_4 + cH_2aFe + bH_2O → Fe_3O_4 + cH_2, the values of aaa, bbb and ccc that balance the equation are:

  1. (a)

    3,4,43,4,43,4,4

  2. (b)

    3,3,43,3,43,3,4

  3. (c)

    2,4,32,4,32,4,3

  4. (d)

    3,4,33,4,33,4,3

Show model answer

Answer: (a) 3,4,43,4,43,4,4.

Balancing iron needs 3Fe3Fe3Fe; the four oxygen atoms in Fe3O4Fe_3O_4Fe_3O_4 need 4H2O4H_2O4H_2O; that supplies 888 hydrogen atoms, giving 4H24H_24H_2. Balanced equation: 3Fe+4H2OFe3O4+4H23Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_23Fe + 4H_2O → Fe_3O_4 + 4H_2.

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Assertion–Reason questions (1 mark)

Q5Assertion–ReasonModerate1 mark

Assertion (A): A chemical equation must always be balanced.

Reason (R): Matter can be neither created nor destroyed in a chemical reaction.

  1. (a)

    Both A and R are true and R is the correct explanation of A

  2. (b)

    Both A and R are true but R is not the correct explanation of A

  3. (c)

    A is true but R is false

  4. (d)

    A is false but R is true

Show model answer

Answer: (a) A balanced equation obeys the law of conservation of mass, which states that matter is neither created nor destroyed; therefore R correctly explains A.

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Very short answer questions (2 marks)

Q6Very ShortEasy2 marks

Define the terms (i) valency and (ii) radical, giving one example of each.

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(i) Valency: The combining capacity of an element, i.e. the number of hydrogen atoms that combine with or replace one atom of that element. Example: the valency of oxygen is 222 (as in H2OH_2OH_2O).

(ii) Radical: An atom or a group of atoms of elements that carries a charge and behaves as a single unit in a chemical reaction. Example: the sulphate radical SO42SO_4^{2-}SO_4^2-.

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Q7Very ShortModerate2 marks

Write the chemical formulae of (i) ammonium carbonate and (ii) calcium hydrogen carbonate.

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(i) Ammonium carbonate: ammonium is NH4+NH_4^{+}NH_4^+ and carbonate is CO32CO_3^{2-}CO_3^2-. Criss-crossing gives (NH4)2CO3(NH_4)_2CO_3(NH_4)_2CO_3.

(ii) Calcium hydrogen carbonate: calcium is Ca2+Ca^{2+}Ca^2+ and hydrogen carbonate (bicarbonate) is HCO3HCO_3^{-}HCO_3^-. Criss-crossing gives Ca(HCO3)2Ca(HCO_3)_2Ca(HCO_3)_2.

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Short answer questions (3 marks)

Q8Short AnswerModerate3 marks

Balance the following chemical equations:

(i) Al+O2Al2O3Al + O_2 \rightarrow Al_2O_3Al + O_2 → Al_2O_3

(ii) KClO3KCl+O2KClO_3 \rightarrow KCl + O_2KClO_3 → KCl + O_2

(iii) Pb(NO3)2PbO+NO2+O2Pb(NO_3)_2 \rightarrow PbO + NO_2 + O_2Pb(NO_3)_2 → PbO + NO_2 + O_2

Show model answer

(i) 4Al+3O22Al2O34Al + 3O_2 \rightarrow 2Al_2O_34Al + 3O_2 → 2Al_2O_3

(ii) 2KClO32KCl+3O22KClO_3 \rightarrow 2KCl + 3O_22KClO_3 → 2KCl + 3O_2

(iii) 2Pb(NO3)22PbO+4NO2+O22Pb(NO_3)_2 \rightarrow 2PbO + 4NO_2 + O_22Pb(NO_3)_2 → 2PbO + 4NO_2 + O_2

In each case the number of atoms of every element is now equal on both sides, satisfying the law of conservation of mass.

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Q9Short AnswerModerate3 marks

Convert the following word equation into a balanced chemical equation with state symbols: 'Zinc reacts with dilute sulphuric acid to give zinc sulphate and hydrogen gas.' State two pieces of information the balanced equation gives that the word equation does not.

Show model answer

Balanced equation:

Zn(s)+H2SO4(aq)ZnSO4(aq)+H2(g)Zn(s) + H_2SO_4(aq) \rightarrow ZnSO_4(aq) + H_2(g)\uparrowZn(s) + H_2SO_4(aq) → ZnSO_4(aq) + H_2(g)

Information the symbolic equation adds:

  1. The exact chemical formulae of reactants and products.

  2. The relative number of atoms/molecules (ratio) taking part and the physical states of each substance.

(It also shows, by the \uparrow, that hydrogen escapes as a gas.)

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Q10Short AnswerEasy3 marks

Complete the table of valencies and give one example compound for each radical.

Show model answer
RadicalSymbol and valencyExample compound
SulphateSO42SO_4^{2-}SO_4^2-CuSO4CuSO_4CuSO_4
NitrateNO3NO_3^{-}NO_3^-KNO3KNO_3KNO_3
PhosphatePO43PO_4^{3-}PO_4^3-Ca3(PO4)2Ca_3(PO_4)_2Ca_3(PO_4)_2
AmmoniumNH4+NH_4^{+}NH_4^+NH4ClNH_4ClNH_4Cl

Each formula is obtained by balancing the positive and negative valencies of the constituent radicals.

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Long answer questions (5 marks)

Q11Long AnswerHOTS5 marks

(a) State the information conveyed by a balanced chemical equation and two of its limitations.

(b) Balance: Fe2(SO4)3+NaOHFe(OH)3+Na2SO4Fe_2(SO_4)_3 + NaOH \rightarrow Fe(OH)_3 + Na_2SO_4Fe_2(SO_4)_3 + NaOH → Fe(OH)_3 + Na_2SO_4.

(c) Write the balanced equation for the action of heat on lead nitrate.

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(a) Information conveyed:

  1. The reactants and products with their correct formulae.

  2. The relative number of molecules and, hence, the mole and mass ratios of the substances.

  3. The physical states and reaction conditions.

Limitations:

  1. It does not tell the speed (rate) of the reaction or the time taken.

  2. It does not indicate the concentration of reactants, whether the reaction is reversible, or the heat/energy change unless specially stated.

(b) Fe2(SO4)3+6NaOH2Fe(OH)3+3Na2SO4Fe_2(SO_4)_3 + 6NaOH \rightarrow 2Fe(OH)_3 + 3Na_2SO_4Fe_2(SO_4)_3 + 6NaOH → 2Fe(OH)_3 + 3Na_2SO_4

(c) 2Pb(NO3)2Δ2PbO+4NO2+O22Pb(NO_3)_2 \xrightarrow{\Delta} 2PbO + 4NO_2\uparrow + O_2\uparrow2Pb(NO_3)_2 → (Δ) 2PbO + 4NO_2 + O_2

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Q12Long AnswerModerate5 marks

(a) What is meant by variable valency? Illustrate with iron and copper.

(b) Write the formulae of ferrous chloride, ferric chloride, cuprous oxide and cupric oxide.

(c) Balance: Cu+HNO3Cu(NO3)2+NO2+H2OCu + HNO_3 \rightarrow Cu(NO_3)_2 + NO_2 + H_2OCu + HNO_3 → Cu(NO_3)_2 + NO_2 + H_2O (concentrated acid).

Show model answer

(a) Variable valency is the property of certain elements of showing more than one valency in their compounds. The lower valency takes the suffix -ous and the higher takes -ic.

Iron: Fe2+Fe^{2+}Fe^2+ (ferrous) and Fe3+Fe^{3+}Fe^3+ (ferric). Copper: Cu+Cu^{+}Cu^+ (cuprous) and Cu2+Cu^{2+}Cu^2+ (cupric).

(b)

  • Ferrous chloride: FeCl2FeCl_2FeCl_2

  • Ferric chloride: FeCl3FeCl_3FeCl_3

  • Cuprous oxide: Cu2OCu_2OCu_2O

  • Cupric oxide: CuOCuOCuO

(c) Cu+4HNO3Cu(NO3)2+2NO2+2H2OCu + 4HNO_3 \rightarrow Cu(NO_3)_2 + 2NO_2\uparrow + 2H_2OCu + 4HNO_3 → Cu(NO_3)_2 + 2NO_2 + 2H_2O

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Case-based questions (4 marks)

Q13Case-basedModerate4 marks

A student is given the word statement: 'Ferric oxide reacts with aluminium to form molten iron and aluminium oxide (the thermite reaction).' Using this, answer the following.

(i) Write the skeletal (unbalanced) chemical equation.

(ii) Balance the equation.

(iii) Identify the substance oxidised and the substance reduced.

(iv) State the law on which the balancing is based.

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(i) Skeletal equation: Fe2O3+AlFe+Al2O3Fe_2O_3 + Al \rightarrow Fe + Al_2O_3Fe_2O_3 + Al → Fe + Al_2O_3

(ii) Balanced equation:

Fe2O3+2Al2Fe+Al2O3Fe_2O_3 + 2Al \rightarrow 2Fe + Al_2O_3Fe_2O_3 + 2Al → 2Fe + Al_2O_3

(iii) Aluminium gains oxygen, so aluminium is oxidised; ferric oxide loses oxygen, so Fe2O3Fe_2O_3Fe_2O_3 is reduced.

(iv) Balancing is based on the law of conservation of mass — atoms are neither created nor destroyed, so the number of atoms of each element must be equal on both sides.

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    Yes — they are aligned to the CISCE latest syllabus syllabus for ICSE Class 9 Chemistry, so nothing here is outside the current course.
  • How should I practise the The Language of Chemistry important questions?
    Attempt each question on paper first, then reveal the model answer to check your method — not just the final result. Re-do anything you got wrong the same day.
  • What types of questions are covered for The Language of Chemistry?
    A full mix — multiple-choice questions, assertion–reason questions, very short answer questions, short answer questions, long answer questions, case-based questions — so every format in the ICSE paper is covered.

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