Study of Compounds: Nitric Acid — ICSE Class 10 Chemistry Important Questions
13 hand-picked ICSE Class 10 Chemistry important questions for Study of Compounds: Nitric Acid, each with a full model answer — the formats and topics most likely to appear in your board exam.
- 13
- Questions
- 6
- Question types
- 32
- Total marks
- ₹0
- With answers
Key ICSE Nitric Acid questions are the Ostwald process manufacture (4NH_3+5O_2→ (Pt)4NO+6H_2O), laboratory preparation from potassium/sodium nitrate and concentrated H_2SO_4, nitric acid as a typical acid with metals and carbonates, its behaviour as a powerful oxidising agent (with copper, sulphur, carbon), the brown ring test for nitrates, and its uses in explosives and fertilisers.
About Study of Compounds: Nitric Acid
In the ICSE Class 10 Chemistry chapter Study of Compounds: Nitric Acid you study its industrial manufacture by the Ostwald process, its laboratory preparation, its acidic reactions with metals, oxides and carbonates, its striking oxidising action (it rarely liberates hydrogen with metals), the brown ring confirmatory test for nitrates, and its important uses.
Key concepts & formulas
Catalytic oxidation of ammonia: 4NH_3+5O_2→ (Pt, 800^ C)4NO+6H_2O; then 2NO+O_2→ 2NO_2 and 4NO_2+O_2+2H_2O→ 4HNO_3.
KNO_3+H_2SO_4(conc.)→ (Δ)KHSO_4+HNO_3. All-glass apparatus is used because the hot vapours corrode rubber and cork; below 200^ C to avoid decomposition of HNO_3.
With copper: dilute acid gives colourless NO, concentrated gives brown NO_2. 3Cu+8HNO_3(dil.)→ 3Cu(NO_3)_2+2NO+4H_2O; Cu+4HNO_3(conc.)→ Cu(NO_3)_2+2NO_2+2H_2O.
Confirmatory test for nitrates: freshly prepared FeSO_4 is added, then conc. H_2SO_4 down the side; a brown ring of [Fe(H_2O)_5NO]SO_4 forms at the junction of the two layers.
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Important questions with answers
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| Question type | Count | Marks |
|---|---|---|
| MCQ | 4 | 1 |
| Assertion–Reason | 1 | 1 |
| Very Short | 2 | 2 |
| Short Answer | 3 | 3 |
| Long Answer | 2 | 5 |
| Case-based | 1 | 4 |
Multiple-choice questions (1 mark)
The catalyst used in the Ostwald process for the manufacture of nitric acid is:
- (a)
Finely divided iron
- (b)
Vanadium pentoxide
- (c)
Platinum (platinum-rhodium gauze)
- (d)
Manganese dioxide
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Answer: (c) Platinum (platinum-rhodium gauze).
Ammonia is catalytically oxidised over hot platinum: 4NH_3+5O_2→ (Pt)4NO+6H_2O.
Concentrated nitric acid is stored in dark bottles because it:
- (a)
Reacts with glass
- (b)
Decomposes in sunlight turning yellow
- (c)
Evaporates quickly
- (d)
Absorbs water
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Answer: (b) Decomposes in sunlight turning yellow.
4HNO_3→ (light)4NO_2+O_2+2H_2O. The dissolved brown NO_2 gives the acid a yellow colour, so it is kept in dark bottles.
When copper reacts with concentrated nitric acid, the gas evolved is:
- (a)
Colourless nitric oxide (NO)
- (b)
Reddish-brown nitrogen dioxide (NO_2)
- (c)
Hydrogen
- (d)
Nitrous oxide (N_2O)
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Answer: (b) Reddish-brown nitrogen dioxide (NO_2).
Cu+4HNO_3(conc.)→ Cu(NO_3)_2+2NO_2+2H_2O.
Very dilute nitric acid (1\%) reacts with magnesium to liberate a gas that burns with a pop sound. This gas is:
- (a)
Nitrogen dioxide
- (b)
Nitric oxide
- (c)
Hydrogen
- (d)
Oxygen
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Answer: (c) Hydrogen.
Only very dilute HNO_3 with the active metals magnesium and manganese behaves as a normal acid: Mg+2HNO_3(very dil.)→ Mg(NO_3)_2+H_2.
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Practise free with the AI tutor →Assertion–Reason questions (1 mark)
Assertion (A): Nitric acid is prepared in the laboratory using an all-glass apparatus.
Reason (R): Hot concentrated nitric acid vapours corrode rubber and cork connections.
- (a)
Both A and R are true and R is the correct explanation of A
- (b)
Both A and R are true but R is not the correct explanation of A
- (c)
A is true but R is false
- (d)
A is false but R is true
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Answer: (a) An all-glass (quickfit) apparatus is used because hot HNO_3 vapour attacks and corrodes rubber and cork; R correctly explains A.
Very short answer questions (2 marks)
Write the equation for the laboratory preparation of nitric acid and state why the temperature is kept below 200^ C.
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KNO_3+H_2SO_4(conc.)→ (Δ)KHSO_4+HNO_3
The temperature is kept below 200^ C because at higher temperatures nitric acid decomposes (4HNO_3→ 4NO_2+O_2+2H_2O), and hot KHSO_4 could form K_2SO_4, which would solidify and clog the apparatus.
What is aqua regia? Give its composition and state one use.
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Aqua regia is a mixture of concentrated hydrochloric acid and concentrated nitric acid in the ratio 3:1 by volume.
It is a very powerful oxidising mixture that can dissolve noble metals such as gold and platinum, which are otherwise unreactive.
Short answer questions (3 marks)
Describe the brown ring test for a nitrate. State the reagents, procedure and the observation.
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Test for nitrate ion (NO_3^-):
- To the salt solution add freshly prepared iron(II) sulphate (FeSO_4) solution and mix.
- Then carefully add concentrated sulphuric acid down the side of the tilted test tube so that it forms a separate lower layer.
Observation: A brown ring appears at the junction of the two liquids, confirming a nitrate. The brown ring is the complex [Fe(H_2O)_5NO]SO_4 formed as nitric acid liberated by H_2SO_4 oxidises Fe^2+ and the resulting NO combines with FeSO_4.
Nitric acid acts both as an acid and as an oxidising agent. Give one equation each to show (i) its acidic reaction with a carbonate and (ii) its oxidising action on carbon.
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(i) Acidic reaction with a carbonate (dilute acid):
Na_2CO_3+2HNO_3→ 2NaNO_3+H_2O+CO_2
Here it behaves as a typical acid, liberating carbon dioxide.
(ii) Oxidising action on carbon (hot concentrated acid):
C+4HNO_3(conc.)→ CO_2+4NO_2+2H_2O
Carbon is oxidised to CO_2 while nitric acid is reduced to brown NO_2, showing its oxidising nature.
Explain why nitric acid rarely liberates hydrogen gas when it reacts with metals. Illustrate with the reaction of dilute nitric acid with copper.
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Nitric acid is a powerful oxidising agent. Any hydrogen that would normally be liberated is immediately oxidised to water by the acid, while the nitric acid itself is reduced to oxides of nitrogen (NO or NO_2) rather than releasing H_2.
With dilute nitric acid, copper gives colourless nitric oxide (which turns brown in air):
3Cu+8HNO_3(dil.)→ 3Cu(NO_3)_2+2NO+4H_2O
No hydrogen is evolved. (Only very dilute acid with magnesium or manganese is the exception, giving H_2.)
Long answer questions (5 marks)
Describe the manufacture of nitric acid by the Ostwald process. Give all the equations, the catalyst and conditions, and represent the stages as a flow diagram.
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In the Ostwald process nitric acid is manufactured by the catalytic oxidation of ammonia.
Stage 1 - catalytic oxidation of ammonia (platinum-rhodium gauze, 800^ C):
4NH_3+5O_2→ (Pt)4NO+6H_2O
Stage 2 - oxidation of nitric oxide (on cooling, in air):
2NO+O_2→ 2NO_2
Stage 3 - absorption in water (with excess air):
4NO_2+O_2+2H_2O→ 4HNO_3
The dilute acid obtained is concentrated by distillation to about 68\%.
(a) Give balanced equations for the action of nitric acid on: (i) copper with concentrated acid, (ii) sulphur with hot concentrated acid. (b) State two uses of nitric acid. (c) Why does concentrated nitric acid render iron passive?
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(a)(i) Copper with concentrated acid:
Cu+4HNO_3(conc.)→ Cu(NO_3)_2+2NO_2+2H_2O
(a)(ii) Sulphur with hot concentrated acid (oxidised to sulphuric acid):
S+6HNO_3(conc.)→ H_2SO_4+6NO_2+2H_2O
(b) Uses of nitric acid:
- Manufacture of nitrogenous fertilisers (e.g. ammonium nitrate, calcium nitrate).
- Manufacture of explosives such as TNT, nitroglycerine and gun-cotton.
(c) Passivity of iron: Concentrated nitric acid oxidises the surface of iron, forming a thin, adherent, unreactive layer of iron oxide (Fe_3O_4) that coats the metal and prevents further reaction. The iron is said to become passive.
Case-based questions (4 marks)
A colourless salt X gives a brown ring when tested, and on heating strongly it leaves a yellow residue with brown fumes and a colourless gas that relights a glowing splint. Answer:
(i) Which anion does the brown ring test confirm to be present in X?
(ii) If X is lead nitrate, write the equation for its action of heat.
(iii) Identify the brown gas and the gas that relights a glowing splint in (ii).
(iv) Name the type of chemical reaction taking place on heating X.
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(i) The brown ring test confirms the nitrate ion (NO_3^-).
(ii) Action of heat on lead nitrate:
2Pb(NO_3)_2→ (Δ)2PbO+4NO_2+O_2
(iii) The brown gas is nitrogen dioxide (NO_2); the gas that relights a glowing splint is oxygen (O_2).
(iv) It is a thermal decomposition reaction. (The yellow residue is lead(II) oxide, PbO.)
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A full mix — multiple-choice questions, assertion–reason questions, very short answer questions, short answer questions, long answer questions, case-based questions — so every format in the ICSE paper is covered.
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