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Study of Compounds: AmmoniaICSE Class 10 Chemistry Important Questions

13 hand-picked ICSE Class 10 Chemistry important questions for Study of Compounds: Ammonia, each with a full model answer — the formats and topics most likely to appear in your board exam.

13
Questions
6
Question types
32
Total marks
₹0
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Quick answer

High-yield ICSE Ammonia questions cover the Haber process (N2+3H22NH3N_2+3H_2\rightleftharpoons 2NH_3N_2+3H_2 2NH_3, iron catalyst, 200 atm\approx200\text{ atm}200 atm, 450-500C450\text{-}500^\circ C450-500^ C), laboratory preparation from ammonium salts, the fountain experiment showing high solubility, ammonia as a base forming ammonium salts, its reducing and complex-forming nature, and the ring test with HClHClHCl. Uses in fertilisers and nitric acid manufacture are frequently asked.

About Study of Compounds: Ammonia

In the ICSE Class 10 Chemistry chapter Study of Compounds: Ammonia you study the industrial Haber process, the laboratory preparation of ammonia, its physical properties (very high solubility shown by the fountain experiment), its chemical behaviour as a base and a reducing agent, its reaction with hydrogen chloride (dense white fumes) and copper(II) ions, and its major industrial uses.

Haber process manufactureLaboratory preparation of ammoniaFountain experiment and solubilityAmmonia as a base and reducing agentTests and industrial uses of ammonia

Key concepts & formulas

Haber process

N2(g)+3H2(g)2NH3(g)N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)N_2(g)+3H_2(g) 2NH_3(g); conditions: pressure 200 atm\approx200\text{ atm}200 atm, temperature 450-500C450\text{-}500^\circ C450-500^ C, finely divided iron catalyst with molybdenum promoter. The reaction is reversible and exothermic.

Ammonia as a base

NH3NH_3NH_3 dissolves in water: NH3+H2ONH4OHNH_3+H_2O\rightarrow NH_4OHNH_3+H_2O→ NH_4OH, giving OHOH^-OH^- ions and turning red litmus blue. It neutralises acids to form ammonium salts, e.g. NH3+HClNH4ClNH_3+HCl\rightarrow NH_4ClNH_3+HCl→ NH_4Cl.

Reducing property

Ammonia reduces heated metal oxides: 3CuO+2NH33Cu+3H2O+N23CuO+2NH_3\rightarrow 3Cu+3H_2O+N_23CuO+2NH_3→ 3Cu+3H_2O+N_2. Black copper(II) oxide turns to reddish-brown copper.

Test for ammonia

Ammonia gas turns moist red litmus blue and gives dense white fumes of NH4ClNH_4ClNH_4Cl with a glass rod dipped in concentrated HClHClHCl.

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Important questions with answers

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Question typeCountMarks
MCQ41
Assertion–Reason11
Very Short22
Short Answer33
Long Answer25
Case-based14

Multiple-choice questions (1 mark)

Q1MCQEasy1 mark

The catalyst used in the Haber process for the manufacture of ammonia is:

  1. (a)

    Platinum

  2. (b)

    Finely divided iron

  3. (c)

    Manganese dioxide

  4. (d)

    Nickel

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Answer: (b) Finely divided iron.

Finely divided iron acts as the catalyst (with molybdenum as promoter) in N2+3H22NH3N_2+3H_2\rightleftharpoons 2NH_3N_2+3H_2 2NH_3.

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Q2MCQEasy1 mark

The drying agent used to dry ammonia gas is:

  1. (a)

    Concentrated H2SO4H_2SO_4H_2SO_4

  2. (b)

    Anhydrous CaCl2CaCl_2CaCl_2

  3. (c)

    Quicklime (CaOCaOCaO)

  4. (d)

    Phosphorus pentoxide (P2O5P_2O_5P_2O_5)

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Answer: (c) Quicklime (CaOCaOCaO).

Ammonia is basic, so acidic drying agents (H2SO4H_2SO_4H_2SO_4, P2O5P_2O_5P_2O_5) and CaCl2CaCl_2CaCl_2 (forms CaCl28NH3CaCl_2\cdot8NH_3CaCl_2·8NH_3) cannot be used. Only quicklime dries it.

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Q3MCQModerate1 mark

When ammonia is passed over heated copper(II) oxide, the observation is:

  1. (a)

    Black solid turns reddish-brown

  2. (b)

    Reddish-brown solid turns black

  3. (c)

    A blue solution is formed

  4. (d)

    White fumes are evolved

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Answer: (a) Black solid turns reddish-brown.

3CuO+2NH33Cu+3H2O+N23CuO+2NH_3\rightarrow 3Cu+3H_2O+N_23CuO+2NH_3→ 3Cu+3H_2O+N_2. Black CuOCuOCuO is reduced to reddish-brown copper, showing ammonia is a reducing agent.

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Q4MCQHOTS1 mark

The addition of excess ammonium hydroxide to a copper(II) sulphate solution finally gives:

  1. (a)

    A pale blue precipitate that dissolves to a deep blue solution

  2. (b)

    A white precipitate

  3. (c)

    A dirty green precipitate

  4. (d)

    No visible change

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Answer: (a) A pale blue precipitate that dissolves to a deep blue solution.

First CuSO4+2NH4OHCu(OH)2+(NH4)2SO4CuSO_4+2NH_4OH\rightarrow Cu(OH)_2\downarrow+(NH_4)_2SO_4CuSO_4+2NH_4OH→ Cu(OH)_2+(NH_4)_2SO_4 (pale blue ppt); with excess it dissolves forming the deep blue complex [Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}[Cu(NH_3)_4]^2+.

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Assertion–Reason questions (1 mark)

Q5Assertion–ReasonModerate1 mark

Assertion (A): Ammonia is collected by the downward displacement of air.

Reason (R): Ammonia is lighter than air and highly soluble in water.

  1. (a)

    Both A and R are true and R is the correct explanation of A

  2. (b)

    Both A and R are true but R is not the correct explanation of A

  3. (c)

    A is true but R is false

  4. (d)

    A is false but R is true

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Answer: (a) Ammonia is lighter than air (so collected by downward displacement of air, i.e. an inverted jar) and is highly soluble (so cannot be collected over water); R correctly explains A.

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Very short answer questions (2 marks)

Q6Very ShortEasy2 marks

Write the balanced equation for the laboratory preparation of ammonia from ammonium chloride and slaked lime, and name the drying agent used.

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2NH4Cl+Ca(OH)2ΔCaCl2+2NH3+2H2O2NH_4Cl+Ca(OH)_2\xrightarrow{\Delta}CaCl_2+2NH_3\uparrow+2H_2O2NH_4Cl+Ca(OH)_2→ (Δ)CaCl_2+2NH_3+2H_2O

The gas is dried by passing it over quicklime (calcium oxide, CaOCaOCaO).

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Q7Very ShortModerate2 marks

State what is observed when a glass rod dipped in concentrated hydrochloric acid is brought near a jar of ammonia. Give the equation.

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Dense white fumes of ammonium chloride are formed.

NH3+HClNH4ClNH_3+HCl\rightarrow NH_4ClNH_3+HCl→ NH_4Cl

This is the standard test used to identify ammonia gas.

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Short answer questions (3 marks)

Q8Short AnswerModerate3 marks

Describe the fountain experiment. What does it demonstrate, and why is the fountain coloured red (or pink)?

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A dry round-bottomed flask is filled with dry ammonia and fitted with a stopper carrying a jet tube and a dropper containing water. A small amount of water is squeezed in from the dropper.

Observation: Ammonia dissolves rapidly, creating a partial vacuum, so water rushes up the jet tube and gushes out as a fountain inside the flask.

It demonstrates that ammonia is extremely soluble in water. If red litmus (or phenolphthalein) is added to the water, the fountain appears blue (or pink) because the ammonia solution (NH4OHNH_4OHNH_4OH) is alkaline.

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Q9Short AnswerModerate3 marks

State the optimum conditions of temperature, pressure and catalyst for the Haber process and explain why a moderate temperature of about 450C450^\circ C450^ C is used rather than a very low temperature.

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Conditions: pressure 200 atm\approx200\text{ atm}200 atm; temperature 450-500C450\text{-}500^\circ C450-500^ C; catalyst finely divided iron with molybdenum as promoter.

N2(g)+3H2(g)2NH3(g)N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)N_2(g)+3H_2(g) 2NH_3(g) (exothermic).

Since the forward reaction is exothermic, a low temperature would favour a higher yield of ammonia, but at low temperature the reaction becomes very slow. A moderate temperature of about 450C450^\circ C450^ C is therefore chosen as a compromise: it gives a reasonable yield of ammonia at an acceptably fast rate.

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Q10Short AnswerHOTS3 marks

Ammonia acts as a reducing agent. Illustrate this with (i) its reaction with heated copper(II) oxide and (ii) its reaction with chlorine (excess chlorine). Give balanced equations.

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(i) With heated copper(II) oxide:
3CuO+2NH33Cu+3H2O+N23CuO+2NH_3\rightarrow 3Cu+3H_2O+N_23CuO+2NH_3→ 3Cu+3H_2O+N_2

Black CuOCuOCuO is reduced to reddish-brown copper; ammonia is oxidised to nitrogen, so it acts as a reducing agent.

(ii) With excess chlorine:
8NH3+3Cl26NH4Cl+N28NH_3+3Cl_2\rightarrow 6NH_4Cl+N_28NH_3+3Cl_2→ 6NH_4Cl+N_2

Ammonia reduces chlorine; the nitrogen of ammonia is oxidised to N2N_2N_2 while Cl2Cl_2Cl_2 is reduced to chloride. (With excess ammonia the products are N2N_2N_2 and NH4ClNH_4ClNH_4Cl; note that with excess chlorine the explosive NCl3NCl_3NCl_3 can form.)

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Long answer questions (5 marks)

Q11Long AnswerModerate5 marks

With a labelled diagram, describe the laboratory preparation of ammonia gas. Include the reactants, equation, method of collection, drying agent, and why concentrated sulphuric acid and calcium chloride are unsuitable drying agents.

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Reactants: an ammonium salt (ammonium chloride) heated with slaked lime.

2NH4Cl+Ca(OH)2ΔCaCl2+2NH3+2H2O2NH_4Cl+Ca(OH)_2\xrightarrow{\Delta}CaCl_2+2NH_3\uparrow+2H_2O2NH_4Cl+Ca(OH)_2→ (Δ)CaCl_2+2NH_3+2H_2O

ICSE Class 10 Chemistry — Study of Compounds: Ammonia: With a labelled diagram, describe the laboratory preparation of ammonia gas. Include the reactants, equation, method of colle

Collection: Ammonia is lighter than air and very soluble in water, so it is collected by the downward displacement of air in an inverted gas jar (not over water).

Drying agent: the gas is dried by passing it over quicklime (CaOCaOCaO).

Unsuitable agents:

  • Concentrated H2SO4H_2SO_4H_2SO_4 and P2O5P_2O_5P_2O_5 are acidic, so they react with basic ammonia: 2NH3+H2SO4(NH4)2SO42NH_3+H_2SO_4\rightarrow(NH_4)_2SO_42NH_3+H_2SO_4→(NH_4)_2SO_4.
  • Anhydrous CaCl2CaCl_2CaCl_2 cannot be used because it forms the compound CaCl28NH3CaCl_2\cdot8NH_3CaCl_2·8NH_3.
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Q12Long AnswerHOTS5 marks

(a) State three important uses of ammonia. (b) Ammonia solution is added drop by drop, and then in excess, to solutions of (i) iron(III) chloride and (ii) zinc sulphate. State the observations and give equations.

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(a) Uses of ammonia:

  1. Manufacture of nitric acid by the Ostwald process.
  2. Manufacture of nitrogenous fertilisers such as urea and ammonium sulphate.
  3. As a refrigerant in ice plants and in the manufacture of washing soda (Solvay process); also in cleaning agents.

(b)(i) Iron(III) chloride: a reddish-brown precipitate of iron(III) hydroxide forms and is insoluble in excess.
FeCl3+3NH4OHFe(OH)3+3NH4ClFeCl_3+3NH_4OH\rightarrow Fe(OH)_3\downarrow+3NH_4ClFeCl_3+3NH_4OH→ Fe(OH)_3+3NH_4Cl

(b)(ii) Zinc sulphate: a white gelatinous precipitate of zinc hydroxide forms, which dissolves in excess ammonium hydroxide to give a colourless solution of the complex.
ZnSO4+2NH4OHZn(OH)2+(NH4)2SO4ZnSO_4+2NH_4OH\rightarrow Zn(OH)_2\downarrow+(NH_4)_2SO_4ZnSO_4+2NH_4OH→ Zn(OH)_2+(NH_4)_2SO_4
Zn(OH)2+4NH4OH[Zn(NH3)4](OH)2+4H2OZn(OH)_2+4NH_4OH\rightarrow[Zn(NH_3)_4](OH)_2+4H_2OZn(OH)_2+4NH_4OH→[Zn(NH_3)_4](OH)_2+4H_2O

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Case-based questions (4 marks)

Q13Case-basedModerate4 marks

A student prepares ammonia in the laboratory and studies its properties. Answer the following:

(i) Name the gas evolved and the colour change it produces on moist red litmus paper.

(ii) The student burns ammonia in an atmosphere of oxygen. Write the equation for ordinary combustion.

(iii) In presence of a heated platinum catalyst, ammonia is catalytically oxidised. Write this equation and name the process it begins.

(iv) Why is ammonia not collected over water?

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(i) Ammonia (NH3NH_3NH_3); it turns moist red litmus blue (it is alkaline).

(ii) Ordinary combustion in oxygen:
4NH3+3O22N2+6H2O4NH_3+3O_2\rightarrow 2N_2+6H_2O4NH_3+3O_2→ 2N_2+6H_2O

(iii) Catalytic oxidation over heated platinum:
4NH3+5O2Pt, 800C4NO+6H2O4NH_3+5O_2\xrightarrow{Pt,\ 800^\circ C}4NO+6H_2O4NH_3+5O_2→ (Pt, 800^ C)4NO+6H_2O

This is the first step of the Ostwald process for manufacturing nitric acid.

(iv) Ammonia is highly soluble in water, so it would dissolve and could not be collected over water.

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