Chapter 5ICSE Class 10 Biology100% Free

TranspirationICSE Class 10 Biology Important Questions

13 hand-picked ICSE Class 10 Biology important questions for Transpiration, each with a full model answer — the formats and topics most likely to appear in your board exam.

13
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6
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32
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High-yield ICSE Transpiration questions cover the definition and types of transpiration (stomatal, cuticular, lenticular), the structure and working of stomata (guard cells), the external and internal factors affecting the rate of transpiration, the significance of transpiration, and differences between transpiration and guttation. A labelled stoma diagram and the Ganong's potometer appear frequently.

About Transpiration

In the ICSE Class 10 Biology chapter Transpiration you study the loss of water in the form of vapour from the aerial parts of a plant, its types, the mechanism of opening and closing of stomata, the factors that affect its rate, experiments to demonstrate and measure it, its significance to the plant, and how it differs from guttation. Diagrams and definitions are emphasised.

Definition and types of transpirationStructure and mechanism of stomataFactors affecting the rate of transpirationSignificance and disadvantages of transpirationTranspiration versus guttation; the potometer

Key concepts & formulas

Transpiration

The loss of water in the form of water vapour from the aerial parts of a plant, mainly through the stomata of leaves. Most transpiration (over 90%) is stomatal.

Stomata and guard cells

Stomata are tiny pores in the epidermis bounded by two bean-shaped guard cells. When guard cells absorb water and become turgid they curve, opening the pore; when they lose water and become flaccid the pore closes.

Factors affecting rate

External factors: light, temperature, humidity, wind (air movement) and available soil water. Higher light, higher temperature, lower humidity and more wind increase the rate of transpiration.

Significance

Transpiration creates the transpiration pull that draws water and minerals up the plant (ascent of sap), cools the plant, and helps maintain the concentration of cell sap; excessive transpiration, however, can cause wilting.

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Important questions with answers

Try each on paper first, then reveal the model answer to check your method.

Question typeCountMarks
MCQ41
Assertion–Reason11
Very Short22
Short Answer33
Long Answer25
Case-based14

Multiple-choice questions (1 mark)

Q1MCQEasy1 mark

Most of the transpiration in a plant takes place through the:

  1. (a)

    Lenticels

  2. (b)

    Cuticle

  3. (c)

    Stomata

  4. (d)

    Root hairs

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Answer: (c) Stomata.

Over 90% of transpiration is stomatal, occurring through the tiny stomatal pores of the leaves.

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Q2MCQEasy1 mark

The cells that guard the stomatal pore and control its opening and closing are the:

  1. (a)

    Epidermal cells

  2. (b)

    Guard cells

  3. (c)

    Mesophyll cells

  4. (d)

    Companion cells

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Answer: (b) Guard cells.

The two bean-shaped guard cells surrounding each stoma open or close the pore by changes in their turgidity.

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Q3MCQModerate1 mark

Which one of the following conditions will decrease the rate of transpiration?

  1. (a)

    High wind speed

  2. (b)

    High humidity

  3. (c)

    High temperature

  4. (d)

    Bright light

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Answer: (b) High humidity.

High humidity reduces the difference in water-vapour concentration between the leaf and the air, so transpiration slows down. The others increase it.

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Q4MCQHOTS1 mark

The loss of water as liquid droplets from the margins of leaves in the early morning is:

  1. (a)

    Transpiration

  2. (b)

    Guttation

  3. (c)

    Bleeding

  4. (d)

    Imbibition

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Answer: (b) Guttation.

Guttation is the loss of water as liquid droplets through special pores (hydathodes) at leaf margins, mainly at night/early morning when root pressure is high and transpiration is low.

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Assertion–Reason questions (1 mark)

Q5Assertion–ReasonModerate1 mark

Assertion (A): The rate of transpiration increases on a hot, dry, windy day.

Reason (R): High temperature and moving air increase the loss of water vapour from the leaf surface.

  1. (a)

    Both A and R are true and R is the correct explanation of A

  2. (b)

    Both A and R are true but R is not the correct explanation of A

  3. (c)

    A is true but R is false

  4. (d)

    A is false but R is true

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Answer: (a) Both statements are true and R explains A: heat raises evaporation while wind removes the humid layer of air around the leaf, both of which speed up transpiration.

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Very short answer questions (2 marks)

Q6Very ShortEasy2 marks

Define transpiration and name its three types.

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Transpiration: The loss of water in the form of water vapour from the aerial (above-ground) parts of a plant, mainly through the stomata of the leaves.

Types: (i) Stomatal transpiration (through stomata), (ii) Cuticular transpiration (through the cuticle of the epidermis), and (iii) Lenticular transpiration (through lenticels of woody stems).

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Q7Very ShortModerate2 marks

Give two differences between transpiration and guttation.

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Transpiration: Water is lost in the form of vapour, mainly through stomata, usually during the day, and the water is pure.

Guttation: Water is lost as liquid droplets, through special pores called hydathodes at leaf margins, usually at night/early morning when root pressure is high, and the droplets may contain dissolved salts.

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Short answer questions (3 marks)

Q8Short AnswerModerate3 marks

Draw a labelled diagram of an open stoma showing the guard cells, chloroplast and stomatal pore.

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A stoma is a pore in the leaf epidermis bounded by two bean-shaped guard cells containing chloroplasts; the inner walls of the guard cells (towards the pore) are thicker than the outer walls.

ICSE Class 10 Biology — Transpiration: Draw a labelled diagram of an open stoma showing the guard cells, chloroplast and stomatal pore.

When the guard cells are turgid, their thin outer walls stretch more than the thick inner walls, so they curve apart and the pore opens.

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Q9Short AnswerEasy3 marks

State any three factors that affect the rate of transpiration and how each affects it.

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(i) Light: Light causes stomata to open, so transpiration increases in bright light and decreases in the dark.

(ii) Temperature: A rise in temperature increases evaporation of water, so the rate of transpiration increases.

(iii) Humidity: High atmospheric humidity lowers the rate of transpiration (less difference in vapour concentration), while dry air increases it.

(Wind speed and available soil water also affect the rate — higher wind increases it.)

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Q10Short AnswerModerate3 marks

Explain the mechanism of opening and closing of stomata.

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The opening and closing of stomata depend on the turgidity of the guard cells.

Opening (in light/day): In the presence of light the guard cells photosynthesise and their osmotic concentration rises (traditionally linked to sugar/starch and K+K^+K^+ accumulation). Water enters the guard cells from the surrounding cells by osmosis, and they become turgid. Because the inner wall (towards the pore) is thick and the outer wall is thin, the turgid guard cells bulge outward and curve apart, so the pore opens.

Closing (in dark/night): In darkness the osmotic concentration of the guard cells falls, water leaves them and they become flaccid. The guard cells straighten and come together, so the pore closes.

Thus stomata are generally open in the day and closed at night.

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Long answer questions (5 marks)

Q11Long AnswerModerate5 marks

(a) List four points of significance (usefulness) of transpiration to a plant. (b) State two harmful effects of excessive transpiration.

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(a) Significance of transpiration:
(i) Ascent of sap: Transpiration creates a transpiration pull that draws water and dissolved minerals upward from the roots to the leaves through the xylem.
(ii) Absorption of water: By continuously removing water from the leaves, it helps the roots to absorb more water from the soil.
(iii) Cooling effect: Evaporation of water during transpiration cools the leaf surface and protects the plant from overheating in strong sunlight.
(iv) Distribution of minerals: The upward stream of water helps distribute mineral salts throughout the plant, and helps keep cells turgid and the concentration of cell sap suitable.

(b) Harmful effects of excessive transpiration:
(i) It can cause wilting and even drying up of the plant when water loss exceeds absorption.
(ii) It reduces the plant's efficiency, as the plant must spend energy and absorb large amounts of water (most of which is lost), and may limit growth during water shortage.

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Q12Long AnswerHOTS5 marks

Describe an experiment using Ganong's potometer to measure the rate of transpiration. State any two precautions and mention one limitation.

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Aim: To measure the rate of transpiration of a leafy shoot.

Apparatus: Ganong's potometer — a graduated horizontal capillary tube connected to a wide tube holding a leafy shoot, with a reservoir; the whole apparatus is filled with water and the capillary tube dips into a beaker of water.

Method:
(i) Cut a healthy leafy shoot under water and fix it air-tight into the potometer, with all joints sealed with grease/vaseline.
(ii) Fill the apparatus completely with water so there are no air bubbles inside.
(iii) Introduce a single air bubble into the open end of the capillary tube by lifting it out of the water for a moment.
(iv) Note the position of the air bubble on the scale and record the distance it moves in a fixed time (say 5 minutes).

Observation: As the shoot transpires, water is drawn in and the air bubble moves towards the plant.

Result: The distance moved by the bubble per unit time gives the rate of water uptake, which is taken as a measure of the rate of transpiration. The reservoir is used to push the bubble back to the start to repeat readings under different conditions (light, wind, humidity).

Precautions: (i) The shoot must be cut and fixed under water and all joints made air-tight to avoid air entering. (ii) Only one air bubble should be introduced and the apparatus kept free of other bubbles.

Limitation: The potometer actually measures the rate of water uptake (absorption), which is only approximately equal to the rate of transpiration, since some absorbed water is used by the plant and not all is transpired.

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Case-based questions (4 marks)

Q13Case-basedModerate4 marks

A well-watered potted plant was enclosed in a transparent polythene bag and kept in bright sunlight for a few hours. Tiny water droplets were seen collecting on the inner surface of the bag.

(i) Name the process responsible for the appearance of the droplets.
(ii) Through which structures of the leaf is most of this water lost?
(iii) If the same plant were kept in the dark instead, how would the amount of water collected change, and why?
(iv) State one way the plant benefits from this process.

Show model answer

(i) The process responsible is transpiration (the water vapour lost condenses on the cool inner surface of the bag).

(ii) Most of this water is lost through the stomata of the leaves.

(iii) In the dark, less water would collect, because in the absence of light the stomata close (guard cells become flaccid) and stomatal transpiration is greatly reduced.

(iv) Transpiration creates a transpiration pull that helps in the upward movement of water and minerals (ascent of sap) — and it cools the plant. Any one benefit is acceptable.

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  • Do these Transpiration questions follow the latest ICSE syllabus?
    Yes — they are aligned to the CISCE latest syllabus syllabus for ICSE Class 10 Biology, so nothing here is outside the current course.
  • How should I practise the Transpiration important questions?
    Attempt each question on paper first, then reveal the model answer to check your method — not just the final result. Re-do anything you got wrong the same day.
  • What types of questions are covered for Transpiration?
    A full mix — multiple-choice questions, assertion–reason questions, very short answer questions, short answer questions, long answer questions, case-based questions — so every format in the ICSE paper is covered.

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