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SoundICSE Class 10 Physics Important Questions

13 hand-picked ICSE Class 10 Physics important questions for Sound, each with a full model answer — the formats and topics most likely to appear in your board exam.

13
Questions
6
Question types
32
Total marks
₹0
With answers
Quick answer

High-yield ICSE Sound questions cover reflection of sound and echoes (using v=2dtv=\dfrac{2d}{t}v=2d/t for distance and the minimum 17m17\,\text{m}17\,m echo condition), natural, forced and resonant vibrations with everyday examples, and the characteristics of a musical sound - loudness (amplitude), pitch (frequency) and quality (waveform). Expect echo numericals and reason-based questions on resonance.

About Sound

In the ICSE Class 10 Physics chapter Sound you study how sound waves are reflected to produce echoes and the conditions and calculations involved, the difference between natural, forced and resonant (sympathetic) vibrations, and the phenomenon of resonance with its examples and demonstrations. You also learn the three characteristics of a musical sound - loudness, pitch and quality (timbre) - and how each depends on amplitude, frequency and waveform respectively.

Reflection of sound and echoesNumericals on speed of sound and echoesNatural, forced and resonant vibrationsResonance and its demonstrationsCharacteristics of sound: loudness, pitch and quality

Key concepts & formulas

Echo and reflection of sound

An echo is a distinct repetition of sound heard after reflection from a distant surface. To hear a separate echo the reflector must be at least 17m17\,\text{m}17\,m away, because the persistence of hearing is 0.1s0.1\,\text{s}0.1\,s: d=v×t2=340×0.12=17md=\dfrac{v\times t}{2}=\dfrac{340\times0.1}{2}=17\,\text{m}d=v× t/2=340×0.1/2=17\,m.

Types of vibration

Natural (free) vibration occurs at a body's own natural frequency once disturbed. Forced vibration is set up by an external periodic force at the force's frequency. Resonance is a special forced vibration where the applied frequency equals the body's natural frequency, giving a large amplitude.

Characteristics of a musical sound

Loudness depends on amplitude (and area of the vibrating body); pitch depends on frequency (higher frequency gives a shriller note); quality (timbre) depends on the waveform, letting us distinguish two instruments sounding the same note.

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Important questions with answers

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Question typeCountMarks
MCQ41
Assertion–Reason11
Very Short22
Short Answer33
Long Answer25
Case-based14

Multiple-choice questions (1 mark)

Q1MCQEasy1 mark

The characteristic of sound that distinguishes a shrill note from a flat note is its:

  1. (a)

    loudness

  2. (b)

    pitch

  3. (c)

    quality

  4. (d)

    speed

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Answer: (b) pitch.

Pitch depends on frequency; a higher frequency gives a shriller (higher-pitched) note and a lower frequency a flatter note.

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Q2MCQEasy1 mark

To hear a distinct echo, the minimum distance of the reflecting surface from the source (taking the speed of sound as 340m s1340\,\text{m s}^{-1}340\,m s^-1) is:

  1. (a)

    1.7m1.7\,\text{m}1.7\,m

  2. (b)

    17m17\,\text{m}17\,m

  3. (c)

    34m34\,\text{m}34\,m

  4. (d)

    170m170\,\text{m}170\,m

Show model answer

Answer: (b) 17m17\,\text{m}17\,m.

d=v×t2=340×0.12=17md=\dfrac{v\times t}{2}=\dfrac{340\times0.1}{2}=17\,\text{m}d=v× t/2=340×0.1/2=17\,m, using the 0.1s0.1\,\text{s}0.1\,s limit of persistence of hearing.

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Q3MCQModerate1 mark

When a vibrating tuning fork is placed on a table, the sound becomes louder. This is an example of:

  1. (a)

    natural vibration

  2. (b)

    forced vibration

  3. (c)

    resonance

  4. (d)

    an echo

Show model answer

Answer: (b) forced vibration.

The fork forces the table top to vibrate at the fork's frequency. The larger vibrating area produces a louder sound, but since the table's natural frequency need not equal the fork's, it is forced (not resonant) vibration.

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Q4MCQHOTS1 mark

A person stands between two parallel cliffs and fires a gun. He hears the first echo after 2s2\,\text{s}2\,s and the next after 3s3\,\text{s}3\,s. If the speed of sound is 340m s1340\,\text{m s}^{-1}340\,m s^-1, the distance between the two cliffs is:

  1. (a)

    340m340\,\text{m}340\,m

  2. (b)

    510m510\,\text{m}510\,m

  3. (c)

    850m850\,\text{m}850\,m

  4. (d)

    1020m1020\,\text{m}1020\,m

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Answer: (c) 850m850\,\text{m}850\,m.

First cliff: d1=340×22=340md_1=\dfrac{340\times2}{2}=340\,\text{m}d_1=340×2/2=340\,m. Second cliff: d2=340×32=510md_2=\dfrac{340\times3}{2}=510\,\text{m}d_2=340×3/2=510\,m. Distance between cliffs =d1+d2=340+510=850m=d_1+d_2=340+510=850\,\text{m}=d_1+d_2=340+510=850\,m.

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Assertion–Reason questions (1 mark)

Q5Assertion–ReasonModerate1 mark

Assertion (A): Soldiers are ordered to break their steps while marching across a suspension bridge.

Reason (R): If the frequency of marching happens to equal the natural frequency of the bridge, resonance can set the bridge into large-amplitude vibrations and it may collapse.

  1. (a)

    Both A and R are true and R is the correct explanation of A

  2. (b)

    Both A and R are true but R is not the correct explanation of A

  3. (c)

    A is true but R is false

  4. (d)

    A is false but R is true

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Answer: (a) Rhythmic marching could match the bridge's natural frequency and cause resonance, building up dangerously large vibrations. Breaking step prevents this, so R correctly explains A.

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Very short answer questions (2 marks)

Q6Very ShortEasy2 marks

(i) What is an echo? (ii) State one practical application of the reflection of sound (echo).

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(i) An echo is the distinct repetition of a sound heard after it has been reflected from a distant hard surface, arriving at the ear at least 0.1s0.1\,\text{s}0.1\,s after the original sound.

(ii) Reflection of sound is used in SONAR / echo-depth sounding to find the depth of the sea or locate objects underwater (or in a stethoscope / megaphone) - any one.

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Q7Very ShortModerate2 marks

State two differences between forced vibrations and resonance.

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Forced vibration: the body vibrates under an external periodic force at the frequency of the applied force, which may differ from the body's natural frequency; the amplitude is generally small.

Resonance: a special case of forced vibration in which the frequency of the applied force equals the natural frequency of the body; the amplitude of vibration becomes very large. Thus every resonance is a forced vibration, but not every forced vibration is resonance.

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Short answer questions (3 marks)

Q8Short AnswerModerate3 marks

A man standing 85m85\,\text{m}85\,m from a tall wall claps his hands and hears the echo 0.5s0.5\,\text{s}0.5\,s later. Calculate the speed of sound in air.

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The sound travels to the wall and back, so it covers twice the distance to the wall.

Total distance =2d=2×85=170m=2d=2\times85=170\,\text{m}=2d=2×85=170\,m.

Time t=0.5st=0.5\,\text{s}t=0.5\,s.

v=total distancetime=2dt=1700.5=340m s1v=\dfrac{\text{total distance}}{\text{time}}=\dfrac{2d}{t}=\dfrac{170}{0.5}=340\,\text{m s}^{-1}v=total distance/time=2d/t=170/0.5=340\,m s^-1

The speed of sound in air is 340m s1340\,\text{m s}^{-1}340\,m s^-1.

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Q9Short AnswerModerate3 marks

Define (i) loudness, (ii) pitch and (iii) quality of a sound, and state the physical quantity on which each depends.

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(i) Loudness: the characteristic by which a loud sound is distinguished from a faint one. It depends on the amplitude of vibration (and on the area of the vibrating body and distance from the source).

(ii) Pitch: the characteristic by which a shrill (high) note is distinguished from a flat (low) note. It depends on the frequency of the sound - higher frequency means higher pitch.

(iii) Quality (timbre): the characteristic that enables us to distinguish between two sounds of the same loudness and pitch produced by different sources. It depends on the waveform (the number and relative intensity of overtones).

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Q10Short AnswerHOTS3 marks

A ship sends a sound signal towards the sea bed and receives its echo after 3s3\,\text{s}3\,s. If the speed of sound in sea water is 1500m s11500\,\text{m s}^{-1}1500\,m s^-1, find the depth of the sea. Why is sound, and not light, used for this purpose?

Show model answer

The sound travels down to the sea bed and back, so it covers twice the depth.

2d=v×t=1500×3=4500m2d=v\times t=1500\times3=4500\,\text{m}2d=v× t=1500×3=4500\,m

d=45002=2250md=\dfrac{4500}{2}=2250\,\text{m}d=4500/2=2250\,m

The depth of the sea is 2250m2250\,\text{m}2250\,m.

Sound is used (in SONAR) rather than light because sound waves can travel long distances through water with little absorption and are strongly reflected by the sea bed, whereas light is quickly absorbed and scattered by water and cannot penetrate to such depths.

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Long answer questions (5 marks)

Q11Long AnswerModerate5 marks

(a) What is resonance? (b) Describe an experiment with two identical pendulums (or tuning forks on sound boxes) to demonstrate resonance. (c) Give one useful and one harmful example of resonance in daily life.

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(a) Resonance is the phenomenon in which a body is set into vibrations with a large amplitude when it is acted upon by a periodic force whose frequency is equal to the natural frequency of the body.

(b) Take two identical tuning forks AAA and BBB of the same frequency, each mounted on its own sound box, and place the open ends of the boxes facing each other. Sound fork AAA with a rubber hammer and then quickly damp it with the hand. Fork BBB is now found to be vibrating and giving out sound. Because both forks have the same natural frequency, the periodic air pressure variations from AAA force BBB into resonant vibration. (Two identical pendulums coupled on a common string behave similarly - energy transfers to the one having the same length/natural frequency.)

(c) Useful: resonance in the air column of musical instruments (flute, sitar) and in a radio-tuning circuit that selects a station. Harmful: resonance can cause a bridge to collapse under rhythmic marching or high winds, and can shatter a glass when a singer's note matches its natural frequency (any one of each).

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Q12Long AnswerHOTS5 marks

(a) State the conditions necessary to hear a distinct echo. (b) A boy standing in front of a cliff fires a gun and hears the echo after 2.5s2.5\,\text{s}2.5\,s. He then moves 170m170\,\text{m}170\,m towards the cliff and fires again, hearing the echo after 1.5s1.5\,\text{s}1.5\,s. Calculate the speed of sound and the original distance of the boy from the cliff.

Show model answer

(a) Conditions for a distinct echo: (i) the minimum distance between the source and the reflecting surface should be 17m17\,\text{m}17\,m (so the reflected sound returns after at least 0.1s0.1\,\text{s}0.1\,s, the limit of persistence of hearing); (ii) the reflecting surface should be large and hard; and the intensity of sound should be sufficient to be heard after reflection.

(b) Let the original distance be ddd and the speed of sound be vvv.

First firing: 2d=v×2.52d=v\times2.52d=v×2.5 ... (1)

After moving 170m170\,\text{m}170\,m closer, distance =(d170)=(d-170)=(d-170): 2(d170)=v×1.52(d-170)=v\times1.52(d-170)=v×1.5 ... (2)

Subtract (2) from (1): 2d2(d170)=v(2.51.5)2d-2(d-170)=v(2.5-1.5)2d-2(d-170)=v(2.5-1.5)

340=v(1.0)v=340m s1340=v(1.0)\Rightarrow v=340\,\text{m s}^{-1}340=v(1.0) v=340\,m s^-1.

From (1): 2d=340×2.5=8502d=340\times2.5=8502d=340×2.5=850, so d=425md=425\,\text{m}d=425\,m.

The speed of sound is 340m s1340\,\text{m s}^{-1}340\,m s^-1 and the boy was originally 425m425\,\text{m}425\,m from the cliff.

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Case-based questions (4 marks)

Q13Case-basedModerate4 marks

A science teacher demonstrates that a vibrating tuning fork of a certain frequency held over an open pipe partly filled with water produces a very loud sound only when the water is adjusted to a particular level.

(i) Name the phenomenon responsible for the loud sound.

(ii) State the condition satisfied by the air column at that particular level.

(iii) The teacher then strikes the same fork harder. Which characteristic of the sound changes, and why?

(iv) If a tuning fork of higher frequency were used, how would the pitch of the sound compare?

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(i) The loud sound is produced by resonance (the air column resonates with the tuning fork).

(ii) At that level the natural frequency of the vibrating air column becomes equal to the frequency of the tuning fork, so the air column vibrates with maximum (large) amplitude and the sound is loudest.

(iii) Striking the fork harder increases the amplitude of vibration, so the loudness of the sound increases. The frequency (pitch) stays the same because it is fixed by the fork.

(iv) A tuning fork of higher frequency produces a note of higher pitch (a shriller sound), since pitch increases with frequency.

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Frequently asked questions

  • Are these Sound important questions free?
    Yes. All 13 ICSE Class 10 Physics important questions for Sound are free, with full model answers and no login required.
  • Do these Sound questions follow the latest ICSE syllabus?
    Yes — they are aligned to the CISCE latest syllabus syllabus for ICSE Class 10 Physics, so nothing here is outside the current course.
  • How should I practise the Sound important questions?
    Attempt each question on paper first, then reveal the model answer to check your method — not just the final result. Re-do anything you got wrong the same day.
  • What types of questions are covered for Sound?
    A full mix — multiple-choice questions, assertion–reason questions, very short answer questions, short answer questions, long answer questions, case-based questions — so every format in the ICSE paper is covered.

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